Let be a strictly increasing sequence of positive numbers. For all
denote as
the least common multiple of the first
terms
of the sequence. Prove that , as
, the following sum converges
Solution


and the original question follows since the sum we seek is less or equal to .
However, we are presenting another proof. Denote as the average order of the numbers
, i.e.,
For any we have
where
is the product of primes not present in the factorization of
. Note that
are squarefree integers. Note also that it may be an empty product, i.e.,
. Then
It is easy to see (and show by induction) that so we have
Hence, Consequently, we have
So the sum of reciprocals of converges. Then, by Cesàro summation, we see that
also converges.
Probably a familiar series for testing of convergence is:
Let
be a a strictly increasing sequence of positive integers. Prove that the series
converges where
denotes the least common multiple.